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【LeetCode 80】删除有序数组中的重复项

·92 words·1 min
WFUing
Author
WFUing
A graduate who loves coding.
Table of Contents

26. 删除有序数组中的重复项
#

class Solution {
    public int removeDuplicates(int[] nums) {
        int left = 0, n = nums.length;
        for(int right = 1; right < n; right++) {
            if(nums[left] != nums[right]) {
                nums[++left] = nums[right];
            }
        }
        return left+1;
    }
}

80. 删除有序数组中的重复项 II
#

class Solution {
    public int removeDuplicates(int[] nums) {
        int n = nums.length;
        if (n <= 2) {
            return n;
        }
        int slow = 0, fast = 2;
        while (fast < n) {
            if (nums[slow] != nums[fast]) {
                nums[slow+2] = nums[fast];
                ++slow;
            }
            ++fast;
        }
        return slow+2;
    }
}